Even First Roll, Sum of Seven

$P(A \mid B) = \frac{1}{2}$, which equals $P(A)$, so $A$ and $B$ are independent.

$P(A \mid B) = 0$, because a sum of 7 forces the first roll to be odd.

$P(A \mid B) = \frac{1}{6}$, which is below $P(A)$, so $A$ and $B$ are dependent.

$P(A \mid B) = \frac{1}{12}$, which is below $P(A)$, so $A$ and $B$ are dependent.