Waiting, Already Waited

Buses arrive at a stop according to a Poisson process at an average rate of one bus every 12 minutes, so the waiting time until the next bus is $X \sim \text{Exponential}(\lambda)$ with $\lambda = \tfrac{1}{12}$ per minute.

You have already stood at the stop for 8 minutes and no bus has come. What is the probability that you must wait at least 6 more minutes? Round to 4 decimal places.

Recall that $P(X > x) = e^{-\lambda x}$.

(Use $e^{-0.5} \approx 0.60653$, $e^{-2/3} \approx 0.51342$, $e^{-7/6} \approx 0.31140$.)