Only One Row of the Inverse

Let

$A = \begin{pmatrix} 2 & -1 & 3 \\ 1 & 4 & 0 \\ 5 & 2 & 1 \end{pmatrix}, \qquad b = \begin{pmatrix} 9 \\ 5 \\ 4 \end{pmatrix}$

The inverse of a $3\times 3$ matrix is

$A^{-1} = \frac{1}{\det(A)}\,\operatorname{adj}(A)$

where $\operatorname{adj}(A)$ is the adjugate of $A$.

Let $x = A^{-1}b$.

What is $x_2$, the second component of $x$? Round your answer to 3 decimal places.