Use the Fundamental Theorem of Calculus to evaluate
∫−12(3x2−4x+1)dx\int_{-1}^{2} \left(3x^{2} - 4x + 1\right) dx∫−12(3x2−4x+1)dx
The curve dips below the axis partway through this interval, so expect a signed total rather than a plain geometric area.
What is the value of the integral?
Select all that apply.
−6-6−6
444
666
222