During a training run the loss L(t)L(t)L(t) changes at the rate
dLdt=3t2−12t+9\frac{dL}{dt} = 3t^2 - 12t + 9dtdL=3t2−12t+9
where ttt is the epoch.
Over the window t=1t = 1t=1 to t=5t = 5t=5, what is the net change L(5)−L(1)L(5) - L(1)L(5)−L(1), and at which epoch in [1,5][1, 5][1,5] is the loss at its lowest?
Select all that apply.
Net change =+16= +16=+16; the loss is lowest at t=3t = 3t=3.
Net change =+20= +20=+20; the loss is lowest at t=3t = 3t=3.
Net change =+24= +24=+24; the loss is lowest at t=3t = 3t=3.
Net change =+16= +16=+16; the loss is lowest at t=1t = 1t=1.